大家好,我做的是一个桩土接触分析问题,想把一个桩从土中拔出,施加两个荷载步,第一步,施加重力荷载,第二步把桩从中拔出,在运行第二步时出了问题,算不下去,请大师不吝指教 ,不胜感激。命令流如下: LF{8hC[
FINI !F Zg'
9
/CLEAR E8lq2r=
&-My[t
/filname,pile-soil contact U9\w)D|+eE
/title,pile +sq_fd ;'D
!/config,nres,2000000 eT2Tg5Etc
/units,si !国际单位制 bq8h?Q
n-GoG(s..b
fe=0.1 !摩擦系数 IO2@^jup
fkn=10 !法向接触刚度 T;,,!
fkt=3!切向接触刚度 CLuQ=-[|
ftoln=1 !初始渗透因子 r0pwKRE~t
fact=2!静动摩擦系数 k2#|^N
p%#'`*<a_
/prep7 Nn?$}g
D mky!Cp
et,1,solid45 ]1[:fQF7/L
IF6-VFY:6
mp,ex,1,7.2e10 !桩的弹性模量,根据管壁厚度折算 \IqCC h
mp,nuxy,1,0.3 !桩的泊松比 q(2ZJn13f
mp,dens,1,2000 !桩的密度 ^nFP#J)_5
!mp,mu,1,fe !桩体性质 5Z:qU{[
HHs!6`R$0c
mp,ex,2,2e8 !土的弹性模量,经验取值 Ue>{n{H"y
mp,nuxy,2,0.3 !土的泊松比 B)P]C5KRD
mp,dens,2,2000 !土的饱和密度 Q/h-Khmz
tb,dp,2 lPtML<a
tbdata,1,0,30 !粘聚力c为0,摩擦角为30 eq<!
(Y^tky$9
!创建桩模型 ]9W7]$
cylind,0,0.1,-0.1,7.1,0,90 Pj!f^MN
!创建土体模型 0fqycGSmU
cylind,0.1,0.6,0,7,0,90 /cvMp#<]
`z7,HJ.0c
!桩体划分网格 VZ
7(6?W
allsel,all wAL}c(EHO
vsel,s,,,1 *!dA/sid
aslv,s (I+e@UUiL
lsla,s *=T(ncR['
lesize,1,,,6 hR.vJ2oa
lesize,2,,,6 h 'Hnq m
lesize,3,,,6 M23r/eg]
lesize,4,,,6 9}4~3_gv;M
lesize,5,,,6 kZi/2UA5Z
lesize,6,,,6 (I35i!F+tY
lesize,7,0.05 MhB>bnWXR
lesize,8,0.05 v?%vB#A^
lesize,9,0.05 |WOc0M[U
type,1 Cbm^:
_LR
mat,1 Imq-5To#
mshape,0,3d Ji6.-[:
mshkey,1 $3%+N|L
vmesh,all lJT"aXt'M
| :id/
vsel,s,,,2 !土层,划分网格 L1y71+iqU
vplot 33&\E- Q>
aslv,s j5]ul!ji
lsla,s - leYR`P
lplot YhC|hDC
lesize,10,,,6 6GqC]rd*:
lesize,11,,,6 f/iMI)J
lesize,12,,,6 3=*ur( Qy
lesize,13,,,6 )8SWU)/
lesize,14,,,6 ,(f W0d#
lesize,15,,,6 j0(jXAc;UB
lesize,16,,,6 ;P/ 4.|<
lesize,17,,,6 k]`-Y E
lesize,18,0.05 @7V~CNB+
lesize,19,0.05 j['B9vG
lesize,20,0.05 GQQp(%T
lesize,21,0.05 *JQ*$$5
type,1 =q`T|9v
mat,2 evNe6J3
mshape,0,3d )}t't"
mshkey,1 m4Ue)
vmesh,all ;K%/sIIke
_+(@?
!创建接触对 ts=:r
!用接触向导建立接触对 Chx+p&!
allsel z0 #2?o
et,2,170 6<R[hIWpZ}
et,3,173 )feZ&G]
r,1 K>b4(^lf
real,1 D!.1R!(Z
keyopt,3,9,0 !消除初始渗透 %H2ios[UO
keyopt,3,12,2 !不分开接触,允许滑动,法向不分开 6]kBG?m0
a6 0rJ#GD
桩侧,建立目标面 ]^>:)q
r,1,,,fkn,ftoln, , , ?:-:m'jdU
rmore,,,,,,fkt E-FR
w
RMORE,,,, ,, '3WtpsKA
RMORE,,,fact,,, 7mMMVz2
mp,mu,3,fe cDE5/!
qMA-#
!创建接触对 I~@8SSO,vH
vsel,s,,,1 7')W+`o8eL
asel,s,,,3 X{OWDy
aplot slUi)@b
cm,target,area SgehOu
type,2 UxzF5V5
real,1 di0@E<@1:
mat,3 w`V6vYd@
nsla,s,1 js@L%1r#L
esurf,all `[U.BVP'
esel,s,type,,2 w D r/T3
eplot ]sk=V.GGQ
/psymb,esys,1 ?+.C@_QZQ
allsel!很重要 GZNN2
'
.9PT)^2
!定义接触面 0<NS1y
vsel,s,,,2 '?L^Fa_H
vplot %A=/(%T>
asel,s,,,9 O=(F46 M
aplot H"6x/&s.=k
cm,contact,area 7bihP@I!
type,3 f:<BUqa
real,1 V|$PO
Qa3
mat,3 31a lQ\TH
nsla,s,1 o5NmNOXm
esurf,all e5P9P%1w
esel,s,type,,3 hr 6j+p:
eplot ^MF 2Q+
/psymb,esys,1 X.k8w\~
allsel iaeNY;T
save %oTBh* K'o
kwc
Cf2
!侧面施加对称约束 F}ATY!
allsel f!w/zC .
CSYS,0 >19s:+
asel,s,loc,x,0 A@)Q-V8*9s
da,all,symm to</
asel,s,loc,y,0 "g&f:[a/
da,all,symm ]h(Iun
?{J1Uw<
allsel,all ,.cR @5qI
!asel,s,,,2!桩顶面2未约束 c]aU}[s1
!da,all,all m{ !$_z8:
asel,s,,,6 pF-_yyQ
da,all,ALL 4=Ru{ewRV
!约束外侧面 fJc(
asel,S,,,8 az0=jou<Zl
NSLA,S,1 EOXkMr
CSYS,1 BoYY^ih
NROTAT,ALL 0't)-Pj+,
D,ALL,UX Yr_B(n
ALLSEL D5@=#/?*
SAVE nsU7cLf"^V
finish!接触对定义结束 s)r!3HS
!求解过程 `D~oY=
/solu _Fa\y ZX
G&{yM2:E
!约束结束! r*vh3.Agl
!定义荷载步 @M4c/k}
!第一步荷载,重力荷载。 &'W7-Z\j-
acel,0,0,9.8 }
u;{38~
nlgeom,on ! 打开大变形选项 |f fHOef
autot,on ! 打开自动时间步 "gM!/<~
time,1 zMbFh_dcq
nsub,10 qm!oJL
outres,all,all QjY}$
allsel +?U[362>
SOLVE cLf90|YFp
!第二部荷载,拉动桩 p;}`PW
nsubst,100,500,5 `J,>#Y6(J
outres,all,all 0<!9D):Bb
time,101 )Y)_T&O
nlgeom,on ! 打开大变形选项 #RR;?`,L}
autot,on ! 打开自动时间步 it\$Pih]
nsel,s,loc,z,7.1 |JIlp"[
D,ALL,UZ,0.1 KMIe%2:b5
SED52$zA
lnsrch,on !自动线性搜索 )
~=pt&+
pred,on !打开预测求解器 zU&Iy_Ke.
+ m-88
allsel J\*uW|=F
SOLVE