Actually you talk about K0 value, my understanding is:
1) Cohesiveless soil, for example, the sand or some granular material , you can use Rankine theory to calculate this K0 value, but it is only for Normal Consolidated soil in primary loading path. In reality, most cases are OC (over consolidated), there is a equation
K0(OC)=f(K0, OCR)=(1-sin(phi)){[OCR/OCRmax^(1-sin(phi))]+0.73*(1-OCR/OCRmax)};
for primary loading: K0=(1-sin(phi))OCR^(sin(phi))
In unloading/reloading path, the K0 value is bigger if you have excavation or backfill.
2)Cohesive soil, such as clay, some empirical equation(relate to PI(plasitic index))
K0(NC)=f(PI)
Such as: K0 (NC)=0.19+0.233log(PI) (Alpan 1967)
3) If the depth is about 100 meter, the response of soil is linear elastic, the soil here is not the same as the normal soil we discussed above. Rankine theory is not suitable here. In finite element, the Poisson's ratio will control this.
[ 此贴被mano在2007-08-12 15:57重新编辑 ]