基底应力 Pk=9200/6*6=255.56Kpa 自重应力 Pc=2.5*19=47.5Kpa
附加应力 P0=255.56-47.5=208Kpa
压缩系数应取47.5~255.56压力段进行计算 47.5对应孔隙比为0.5345, 255.56对应0.507
求得压缩系数为a=(0.5345-0.507)/208=0.132Mpa-1
压缩模量为E=(1+0.5345)/0.132=11.625Mpa
应力面积 2*(1+0.86)/2+2*(0.86+0.55)/2+1.5*(0.38+0.55)/2=3.9675
沉降量S=0.4*208*3.9675/(11.625*1000)=28.4mm
哪里错了呀????