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我的这个模拟是基于这样一个问题:采矿中开挖4条同样支护方式的巷道,但是巷道的位置不同(煤柱的宽度不同) iX]tL:,~i
;在其中使用了几重循环,可能对初学者有参考价值,我也常常看论坛的资料,现在自己贡献一点。 t4Q&^AC
;这个文件可以直接运行的。 ,>
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;建立网格 820m*900m*350m 网格51*30*30=4.59万网格 _tba:a(
gen zone brick size 10 30 4 & 92F9)S{"
p0 0 0 0 p1 295 0 0 p2 0 900 0 p3 0 0 40 ratio 0.8 1 1 $U*b;'o
gen zone brick size 8 30 4 & msf%i !
p0 295 0 0 p1 335 0 0 p2 295 900 0 p3 295 0 40 zE,1zBS<
gen zone brick size 15 30 4 & t=(d, kf
p0 335 0 0 p1 485 0 0 p2 335 900 0 p3 335 0 40 NeI#gJ1A
gen zone brick size 8 30 4 & $I*<gn9
p0 485 0 0 p1 525 0 0 p2 485 900 0 p3 485 0 40 b8FSVV
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gen zone brick size 10 30 4 & g"}j
p0 525 0 0 p1 820 0 0 p2 525 900 0 p3 525 0 40 ratio 1.25 1 1 oy[>`qyz
gen zone brick size 10 30 10 & S{d]0
p0 0 0 40 p1 295 0 40 p2 0 900 40 p3 0 0 50 ratio 0.8 1 1 {TOz}=R"3h
gen zone brick size 8 30 10 & >f\$~cp
p0 295 0 40 p1 335 0 40 p2 295 900 40 p3 295 0 50 #[odjSb
gen zone brick size 15 30 10 & c^F@9{I
p0 335 0 40 p1 485 0 40 p2 335 900 40 p3 335 0 50 m#Y[EPF=|
gen zone brick size 8 30 10 & 9*Z!=Y#4,
p0 485 0 40 p1 525 0 40 p2 485 900 40 p3 485 0 50 bJ!(co6t
gen zone brick size 10 30 10 & (fqU73
p0 525 0 40 p1 820 0 40 p2 525 900 40 p3 525 0 50 ratio 1.25 1 1 y8.3tp
gen zone brick size 10 30 6 & DeK&_)g| Z
p0 0 0 50 p1 295 0 50 p2 0 900 50 p3 0 0 110 ratio 0.8 1 1 "=Xky,k
gen zone brick size 8 30 6 & ;owU]Xk%8K
p0 295 0 50 p1 335 0 50 p2 295 900 50 p3 295 0 110 yg WwUpY
gen zone brick size 15 30 6 & yd=NafPM
p0 335 0 50 p1 485 0 50 p2 335 900 50 p3 335 0 110 16-1&WuY@
gen zone brick size 8 30 6 & wn Q% 'Eo
p0 485 0 50 p1 525 0 50 p2 485 900 50 p3 485 0 110 Nu,t,&B
gen zone brick size 10 30 6 & K3;~|U-l
p0 525 0 50 p1 820 0 50 p2 525 900 50 p3 525 0 110 ratio 1.25 1 1 MhDPf]`
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gen zone brick size 10 30 10 & ET\>cxSp
p0 0 0 110 p1 295 0 110 p2 0 900 110 p3 0 0 350 ratio 0.8 1 1.25 49!(Sa_]j
gen zone brick size 8 30 10 & =38c}(
p0 295 0 110 p1 335 0 110 p2 295 900 110 p3 295 0 350 ratio 1 1 1.25 Yc`PK =!l
gen zone brick size 15 30 10 & KN<KZM
p0 335 0 110 p1 485 0 110 p2 335 900 110 p3 335 0 350 ratio 1 1 1.25 pY$DOr-r`
gen zone brick size 8 30 10 & Bk;/>gD
p0 485 0 110 p1 525 0 110 p2 485 900 110 p3 485 0 350 ratio 1 1 1.25 pP)> x*1
gen zone brick size 10 30 10 & Ha/Gn!l
p0 525 0 110 p1 820 0 110 p2 525 900 110 p3 525 0 350 ratio 1.25 1 1.25 :G4)edwe
WR zIK09@
;本构关系、参数 dTVh{~/
m m t~V?p'a0ys
prop den=2700 bulk=15e9 shear=60e8 fric=42 coh=2.61e6 range z 0 44 p?,T%G+gqO
prop den=1500 bulk=1e9 shear=4e8 fric=30 coh=1.4e6 range z 44 50 ~Q2,~9Dkc
prop den=2700 bulk=15e9 shear=60e8 fric=42 coh=2.61e6 range z 50 350 5E!Wp[^
;边界、初始条件 OrRU$5Lo
fix z range z -0.1 0.1 K)P].htw
fix x range x -0.1 0.1 v$~ZT_"(9
fix x range x 819.9 820.1 zwgO|Qg;
fix y range y -0.1 0.1 %df[8eX{
fix y range y 899.9 900.1 4"et4Y7
;重力梯度化 _zG[b/:p
set grav 0 0 -10 rPx:o}&<
ini szz -9.45e6 grad 0,0,2.7e4 range z 50 350 MT^krv(G
ini szz -8.85e6 grad 0,0,1.5e4 range z 44 50 yv(\5)XF
ini szz -9.378e6 grad 0,0,2.7e4 range z 0 44 mNQ*YCq.
hist unbal BDcA_=^R&
plot set plane nor 0 1 0 origin 0 100 0 P"s7}cl
plot con szz plan JL=s=9N;3
step 3000 w1,6%?p(O
hist unbal vq8&IL
save 4001.sav +"3K)9H
;没开挖前的的自重平衡,为状态1 oLc
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rest 4001.sav n_S)9C'=
;开挖巷道 +`+r\*C5
ini state=0 yL"pzD`[H
ini xdis 0 ydis 0 zdis 0 *k
!zdV
ini xvel 0 yvel 0 zvel 0 =P`l+k3
;以下是自己写的几重循环的嵌套,可能对初学者有用。 6B&ERdoX
;开挖四条巷道加锚杆支护的实验 lQt* LWd[
;定义一个函数 aa_2 ]GmXZi
def aa_2 L=)Arj@q
;定义一个循环变量 aaa,为了实现在不同位置开挖4条同样参数巷道,巷道位置循环,循环1 x0ICpt{;
loop aaa (1,4) !^IAn
caseof aaa ;oJCV"y6$
case 1 X@^"@
x_d1=295 !A#(bC
case 2 (E<QA
x_d1=520 5tcJTz
;10m煤柱 YnwP\Arfq
case 3 OO-b*\QW
x_d1=310 }Oe9Zq
case 4 ?gl[=N V
x_d1=505 O;SD90
end_case ky{-NrK
;定义几个变量,在下面的循环中要用到 :'K%&e?7s
;左帮锚杆的起、终点变量
3vRBK?Q.y
x_d11=x_d1-1.4 M|\C@,F]8
;右帮锚杆的起、终点变量 wf/DLAC
x_d2=x_d1+5 %z5P%F'5
x_d21=x_d2+1.4 &?#!%Ds
;开挖巷道 /]hE?cmj
command .>+jtp}
model null range x x_d1 x_d2 y 0 900 z 44 47 Fy-|E>@]D
endcommand '`/w%OEVC5
;在一定的范围内给巷道加锚杆,加帮锚杆和顶锚杆 50Y^##]&
loop k (250,500) .+2@(r
y_d=k*0.8-0.8 Vv~:^6il
;帮锚杆的参数及循环,每帮加3个锚杆 ;&U! g&
loop a_2(1,3) :P:OQ[$
z_d1=44.0 [cvtF(,
z_d1=z_d1+0.7*a_2 UWW_[dJr
;左、右两帮锚杆的定义 0OPpA Ll
command Y|y X]\,
sel cable beg x_d1,y_d,z_d1 end x_d11,y_d,z_d1 nseg 4 h0n,WU/Kw
sel cable beg x_d2,y_d,z_d1 end x_d21,y_d,z_d1 nseg 4 qFg"!w
sel cable prop emod 2e10 ytens 2.5e8 xcarea 1.0 gr_coh 1e10 gr_k 2e10 gr_per 1.0 h;Se.{
endcommand 4&/m>%r
end_loop HA::(cXL
;顶锚杆的参数及循环,顶锚杆加6根 Ialbz\;F2%
loop a_3(1,6) z9IJ%=R
x_d3=x_d1 $][$ e
x_d3=x_d3+0.7*a_3 Q2HULz{
;顶锚杆的定义 oCR-KR>{Q
command m-)yQM8
sel cable beg x_d3,y_d,47 end x_d3,y_d,48.4 nseg 4 H_+F~P5RC
sel cable prop emod 2e10 ytens 2.5e8 xcarea 1.0 gr_coh 1e10 gr_k 2e10 gr_per 1.0 Ceco^Mw
endcommand (v$$`zh
end_loop - |j4u#z
;结束每一个循环,大家可以根据位置来判断对应关系 s^Wh!:>r/
end_loop $jtXNE?
end_loop _Vf0MU;3f+
end ( R0>0f@
aa_2 RmcQGQ
step 500 Vs~!\<?
;开挖工作面、软化顶板 XVNJ3/
ini state=0 /pOK4"
model null range x 300 520 y 300 600 z 44 47 ;采底煤 T{Rhn V1
step 500 #I|jFn9
model null range x 300 520 y 300 600 z 47 50 ;放顶煤 ~76qFZe-
prop den=2700 bulk=7.5e9 shear=30e8 fric=42 coh=1.3e6 range x 300 520 y 300 600 z 50 70 E]26a,^L
step 1000 E^<.;
save 401.sav Z$&