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用MATLAB自带卷积分函数计算弹性半空间在一三角脉冲荷载下自由表面的竖向位移,与文献正确结果相差10的5次方倍,但自己编写卷积分代码,反而得到文献结果。请大家帮我看下问题出在哪?谢谢! F[`dX Bx#=$ka 另外,为何MATLAB自带卷积分函数结果矩阵的维数会是被卷积两矩阵维数之和减1? %\n|2*r "Aw)0a[j1 1. 问题描述,如下图1所示: A^A)arJS n${k^e-= bovAFdHW 7mMMVz2 2. 格林函数,如下图2所示: .>P:{'' cDE5/! Ym!e}`A\F qMA-# 3. 参考文献正确解,如下图3所示: zNdkwj p+ cC+2%q B 4v3gpLH Pd(_ 4. 本人直接用自编卷积分MATLAB代码算的出解(如下图4)及相应代码: F"O\uo:3 i. (Af$ Ki7t?4YE <c:H u{D clear; 8N?D1;F; clc; slUi)@b h:r?:C>n %loading history SgehOu :Jv5Flxl dt=0.01; k+w Ji ti=0.0008; W I MBwmg te=12; u*rP8GuS t=ti:dt:te; rD a{Ve pt=(10*t./1.5).*(t>=0 & t<=1.5)+(20-10*t./1.5).*(t>1.5 & t<=3)+0.*(t>3); 1 <+aF, m=length(pt); &>E gKL hqmE]hwc %load distribution in space j%^4
1 y L/`1K_\l rp=0.1; x&0kIF'lq ri=0; Hq 3V+$ rc=0.1; ]sk=V.GGQ dr=0.001; |5O>7~Tp r=ri:dr:rc; ?+.C@_QZQ pr=1*(r<=rp)+0*(r>rp); +F2OPIanT~ n=length(pr); lw.[qP 2A[hMbL %load function with respect to t and r q CYu@Ho ) ba~7A p=pr.'*pt; ?+^p$'5 1gbFl/i6T %green's function zyUS$g]& L\E>5G; G=1; l:uQ#Z) cs=1; IDFzyg_ for i=1:1:m +>K&zS for j=1:1:n c@3 5\!9 u(j,i)=heaviside(cs*t(i)-r(j))/(pi*G*sqrt(t(i)^2-(r(j)/cs)^2)); Qz#By V: end 7bihP@I! end Ve&_NVPrd f:<BUqa %convolution and response of displacement vZ"gCf3#?3 FiUwy/,ZV for i=1:1:m "QxULiw for j=1:1:n j-W$)c3X v(j,i)=0; /#H P;>!n for k=1:1:i ^jwzCo- for g=1:1:j #?jsC) v(j,i)=v(j,i)+p(g,k)*u(j-g+1,i-k+1)*dr*dt; ipbhjK$ end; #~"IlBk\ end; Y%;X7VxU* end; fx[&"$X end; :TG;W,`.V Ez5t)l- %plot the response history zIjfxK J&,hC%] plot(t,v(n,); ~uty<fP xlabel('t/s'); XGH:'^o_ ylabel('v/m'); kwc
Cf2 grid on;
h-?yed*? title('response of point A or C'); Oh p@ZJ!a? TnK<Wba 5. 直接用MATLAB自带卷积分算的出解(如下图5)及相应代码: 5~@-LXqL bS r"k xd^Pkf Y$A2{RjRq clear; 5P"R'/[PA_ clc; iC=>wrqY> KGg
S"d %loading history aSX4~UYB= X~0-W Bz dt=0.01; Vb\g49\o/ ti=0.0008; A#T"4'#?< te=12; 4^l 9d t=ti:dt:te; n+ebi>}P pt=(10*t./1.5).*(t>=0 & t<=1.5)+(20-10*t./1.5).*(t>1.5 & t<=3)+0.*(t>3); Pd"c*n&9 m=length(pt); C1=&Vm>g+ ~io. TS|r %load distribution in space 8X"4RyNSn 9$;5J rp=0.1; ~1wt=Ln> ri=0; tJrGRlB> rc=0.1; 0P9\; !Y dr=0.001; n-cI~Ax+4 r=ri:dr:rc; fI<LxU_n: pr=1*(r<=rp)+0*(r>rp); xw
43P. n=length(pr); az0=jou<Zl d\]KG(T %load function with respect to t and r v#%rjml[ QhJN/v
p=pr.'*pt; A+* lV*@0 0lg'QG> %green function vjx'yh| +u0of^}= G=1; zdrP56rzZ cs=1; o?>0WSLlm for i=1:1:m 8:V,>PH for j=1:1:n @tm2Y%Y! u(j,i)=heaviside(cs*t(i)-r(j))/(pi*G*sqrt(t(i)^2-(r(j)/cs)^2)); z}u`45W+ end s)r!3HS end !~~KM?g `D~oY= %convolution and response of displacement
&kmaKc %"A8Af**I v=conv2(u,p); /-[vC$B" y
2>
93m
%plot the response history p7;K] AW -@"3`uv" rr=r(n); PKrG6%
W+ [tpu,rpu]=meshgrid(ti:dt:2*te-dt,ri:dr:2*rc); 9d#?,:JG [X,Y,Z]=meshgrid(linspace(min(tpu(),max(tpu()),linspace(min(rpu(),max(rpu()),linspace(min(v(),max(v())); *pa hZiO V=Y; '`k7l7I[@ h=contourslice(X,Y,Z,V,tpu,rpu,v,[0 0]+rr); yV:8>9wE8 set(h,'edgecolor','k'); B]G2P`sN contourslice(X,Y,Z,V,tpu,rpu,v,[0 0]+rr); ue@/o,C> xlabel('t/s'); HJ7A/XW ylabel('r/m'); zMbFh_dcq zlabel('v/m'); M1-tRF axis([0 12 0 0.1 0 12e4]); qm!oJL view(0,0); ="& GU%$ grid on; ;7:} iKU title('displacement response history of point A or C');
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