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[求助]基坑支护flac 3的模拟 [复制链接]

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只看楼主 倒序阅读 使用道具 楼主  发表于: 2013-09-28
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new \5P 5N]]  
gen zone brick p0 0 0 0 p1 80 0 0 p2 0 80 0 p3 0 0 30 size 40 40 15 >UnLq:G  
model  mohr XImX1GH  
prop bulk 9.2e10 shear 4.7e10 fric 50 }Uue}VOA  
prop coh 1e10 tens 1e10 `MC5_SG 1  
set grav 0 0 -10 C Ef*:kr  
ini dens 2000 l1%ubu  
fix x y range x -0.1 0.1 !uW;Ea?  
fix x y range x  79.5 80.5 I_5[-9  
fix x y range y -0.1 0.1 wK!7mZ  
fix x y range y  79.5 80.5 p\22_m_wd  
fix x y z range z -0.1 0.1 ;pt.)5  
p`)Mk<`dYD  
hist id=1 unbal M3!4,_!~  
solve ^H`4BWc  
save chushiyingli.save p735i`8  
t03T1.:(Mg  
prop bulk 2.06e7 shear 1.01e7 fric 8 coh 15e3 WP5Vev9*+  
!:c_i,N  
set large GJIZu&C  
ini xdis 0 ydis 0 zdis 0 q+2v9K@  
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sel pile prop density=2500 [h !i{QD  
7U?#Xi5  
sel pile prop Emod=8.0e10 Nu=0.25 XCArea=0.1963  & .p> ".q I  
              XCJ=6.13e-3 XCIy=3.07e-3  XCIz=3.07e-3  & iOSt=-p  
              Per=1.57 & gs=ok8w  
              CS_sK=2e8 CS_sCoh=0    CS_sFric=0.0 & )WW*X6[k  
              CS_nK=1.3e20 CS_nCoh=0 CS_nFric= 15.0 CS_nGap=off Lusd kc7  
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model mech null range x 20 60  y 20 60 z 29 30 <mj/P|P@  
}q'IY:r  
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sel beam id 4 begin=(20,20,30)  end=(60,20,30)  nseg=20 t\'MB  
sel beam id 4 begin=(60,20,30)  end=(60,60,30)  nseg=20 [@JK|50|K  
sel beam id 4 begin=(20,60,30)  end=(60,60,30)  nseg=20 pKGhNIj$  
sel beam id 4 begin=(20,20,30)  end=(20,60,30)  nseg=20 O[{/P:a  
x*RSD,3  
sel beam prop emod=2.0e11 nu=0.25 nC!]@lA  
sel beam prop XCArea=0.6 XCIz=0.0256 XCIy=0.0144 XCJ=0.03 i$`o,m#  
12?!Z  
r:$*pC&{  
SEL JOIN beam ID  4 pile ID 3 RANG Z 29.9 30.1 m#i4_F=^b  
SEL JOIN beam ID 4 beam ID 4 RANG Z 29.9 30.1 e|5@7~Vi  
|yz o|%]3  
hist id=2 unbal -iY-rzW  
step 5000 60 cQ3.e  
save gongkuang1.save f F)M'C  
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model mech null range x 20 60  y 20 60 z 22 29 =wW M\f`=  
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hist id=3 unbal JbJ!,86  
step 5000 cruBJZr*  
save gongkuang2.save =:zPT;K  
@YQ*a4`  
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model mech null range x 20 60  y 20 60 z 18 29 /#SfgcDt  
z wRF-{s  
hist id=4 unbal 8 hhMuh  
step 5000 &BNlMF  
save gongkuang3.save sD2,!/'  
基坑尺寸40m×40m×12m,采用φ500的悬臂桩支护桩,请问一下各位老师为什么我模拟出的支护桩和桩后土向坑外移动?请老师们帮忙看看是不是桩的参数和冠梁参数取错了。 v\MQ?VC  
这是基坑y向位移的一张云图。请各位老师帮我找下原因。
1条评分土币+3
沈建韩旭 土币 +3 - 2013-11-13
离线kunshan_zqs

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只看该作者 1楼 发表于: 2013-09-28
建议你仔细看看程序,你垂直方向取了30米,划分了15个单元格,每个单元格是2米,挖土阶段怎么会出现29米?
1条评分土币+3
须胡白 土币 +3 向您学习,牛人 2013-09-29
离线须胡白

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只看该作者 2楼 发表于: 2013-09-28
回 kunshan_zqs 的帖子
kunshan_zqs:建议你仔细看看程序,你垂直方向取了30米,划分了15个单元格,每个单元格是2米,挖土阶段怎么会出现29米? (2013-09-28 22:54)  Wa.xm_4s2  
}uC]o@/  
首先谢谢您的解答。29m是施工冠梁的第一个工况!
离线kunshan_zqs

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只看该作者 3楼 发表于: 2013-09-30
如果对半个单元的材料参数取为零,程序上是否允许,或者会出现什么状况?你是否可以考虑把上面28至30之间划为两层单元
离线须胡白

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只看该作者 4楼 发表于: 2013-09-30
回 kunshan_zqs 的帖子
kunshan_zqs:如果对半个单元的材料参数取为零,程序上是否允许,或者会出现什么状况?你是否可以考虑把上面28至30之间划为两层单元 (2013-09-30 14:59)  "M-';;  
Jq(;BJ90R  
我找到原因了,是桩的侧向刚度和粘结强度取值太大了,我调整了一下过去了。你的将28至30划分为两个单元,也是有理的,我试过如果将桩设置在网格中间,比如说20.5的位置处,就不能计算了,不知道这是什么原因……

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只看该作者 5楼 发表于: 2014-02-22
修改后的模拟效果可否给大家看一下呢
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