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[求助]基坑支护flac 3的模拟 [复制链接]

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离线须胡白
 

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只看楼主 倒序阅读 使用道具 楼主  发表于: 2013-09-28
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new .5Y{Yme  
gen zone brick p0 0 0 0 p1 80 0 0 p2 0 80 0 p3 0 0 30 size 40 40 15 <CVX[R]U  
model  mohr Nx.9)MjI  
prop bulk 9.2e10 shear 4.7e10 fric 50 {%3WHGr%L  
prop coh 1e10 tens 1e10 "yw{A%J  
set grav 0 0 -10 @ 3=pFYW)  
ini dens 2000 p"hO6b%V  
fix x y range x -0.1 0.1 0;TiNrzg  
fix x y range x  79.5 80.5 oUnb-,8n  
fix x y range y -0.1 0.1 &5-1Cd E  
fix x y range y  79.5 80.5 anW['!T9{s  
fix x y z range z -0.1 0.1 w3(G!:  
[nxYfER7  
hist id=1 unbal 4N,[Gs<7  
solve )r46I$]>  
save chushiyingli.save SEI0G_wk$  
clU ?bF~e1  
prop bulk 2.06e7 shear 1.01e7 fric 8 coh 15e3 E'\gd7t ;  
*}89.kCBF  
set large G{: B'08  
ini xdis 0 ydis 0 zdis 0 !d()'N  
# QwX|x{  
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sel pile prop density=2500 y-7$HWn  
4d]T`  
sel pile prop Emod=8.0e10 Nu=0.25 XCArea=0.1963  & 74Il]i1=  
              XCJ=6.13e-3 XCIy=3.07e-3  XCIz=3.07e-3  & {uO2m*JrI  
              Per=1.57 & s9YP =)I  
              CS_sK=2e8 CS_sCoh=0    CS_sFric=0.0 & 9TE-'R@  
              CS_nK=1.3e20 CS_nCoh=0 CS_nFric= 15.0 CS_nGap=off  7w|4BRL  
Dmk~t="Y  
model mech null range x 20 60  y 20 60 z 29 30 }15ooe%  
k@C]~1  
j0K}nS\ P  
sel beam id 4 begin=(20,20,30)  end=(60,20,30)  nseg=20 '"Dgov$q  
sel beam id 4 begin=(60,20,30)  end=(60,60,30)  nseg=20 u/ 74E0$S  
sel beam id 4 begin=(20,60,30)  end=(60,60,30)  nseg=20 +(2mHS0_a  
sel beam id 4 begin=(20,20,30)  end=(20,60,30)  nseg=20 1j^FNg ~  
2fJ2o[v  
sel beam prop emod=2.0e11 nu=0.25 S|v-lJ/I  
sel beam prop XCArea=0.6 XCIz=0.0256 XCIy=0.0144 XCJ=0.03 T$xY]hqr  
Z}6H529[  
}"9jCxXL  
SEL JOIN beam ID  4 pile ID 3 RANG Z 29.9 30.1 L}U fd >*  
SEL JOIN beam ID 4 beam ID 4 RANG Z 29.9 30.1 e0u* \b  
N|WR^MQD  
hist id=2 unbal 0 Pa\:^/6  
step 5000 !TuMrA *  
save gongkuang1.save @GR|co  
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model mech null range x 20 60  y 20 60 z 22 29 9L xa?Y1  
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hist id=3 unbal -Z%B9ql'  
step 5000 "^@0zy@x  
save gongkuang2.save E2{SKIUm  
>&N8Du*[  
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model mech null range x 20 60  y 20 60 z 18 29 >sE{c>R%  
,U/ZG|=v  
hist id=4 unbal oBTRO0.s+  
step 5000 fDY#&EO: %  
save gongkuang3.save  ^'c[HVJ  
基坑尺寸40m×40m×12m,采用φ500的悬臂桩支护桩,请问一下各位老师为什么我模拟出的支护桩和桩后土向坑外移动?请老师们帮忙看看是不是桩的参数和冠梁参数取错了。 E MKv)5MH  
这是基坑y向位移的一张云图。请各位老师帮我找下原因。
1条评分土币+3
沈建韩旭 土币 +3 - 2013-11-13
离线kunshan_zqs

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只看该作者 1楼 发表于: 2013-09-28
建议你仔细看看程序,你垂直方向取了30米,划分了15个单元格,每个单元格是2米,挖土阶段怎么会出现29米?
1条评分土币+3
须胡白 土币 +3 向您学习,牛人 2013-09-29
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只看该作者 2楼 发表于: 2013-09-28
回 kunshan_zqs 的帖子
kunshan_zqs:建议你仔细看看程序,你垂直方向取了30米,划分了15个单元格,每个单元格是2米,挖土阶段怎么会出现29米? (2013-09-28 22:54)  UmSy p\i  
$5`P~Q'U  
首先谢谢您的解答。29m是施工冠梁的第一个工况!
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只看该作者 3楼 发表于: 2013-09-30
如果对半个单元的材料参数取为零,程序上是否允许,或者会出现什么状况?你是否可以考虑把上面28至30之间划为两层单元
离线须胡白

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只看该作者 4楼 发表于: 2013-09-30
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kunshan_zqs:如果对半个单元的材料参数取为零,程序上是否允许,或者会出现什么状况?你是否可以考虑把上面28至30之间划为两层单元 (2013-09-30 14:59)  LE!xj 0  
)a ov]Ns  
我找到原因了,是桩的侧向刚度和粘结强度取值太大了,我调整了一下过去了。你的将28至30划分为两个单元,也是有理的,我试过如果将桩设置在网格中间,比如说20.5的位置处,就不能计算了,不知道这是什么原因……

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只看该作者 5楼 发表于: 2014-02-22
修改后的模拟效果可否给大家看一下呢
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