在做隧道ANSYS简单开挖模拟时,出现了一些问题,望各位前辈给多多指教! d7X&3L%Oq
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隧道洞泾假定为1.0m(实际上不可能这么小,仅仅是数值实验),隧洞轴线左右及下部各取10m为边界,施加法向约束。 EbQLMLD%
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通过APDL命令,改变隧道的轴线埋深,采取全断面一次性开挖,整个荷载步分为两步:第一步计算初始应力场,第二步是杀死 '3( ^Zv
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开挖体单元,计算开挖后引起的地表沉降(位移场,第二步减去第一步),计算结果发现: G-Tmk7m
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隧道的轴线埋深越浅,计算得到的地表沉降越小,这与工程实际不符,请问原因何在? }#O!GG{
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以下是我的计算命令流,希望得到高手的帮助啊! oY18a*_>M1
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}p7iv:P=3
Fini Z nc(Q
/clear }6c>BU}DF
/title,TUNNEL ANALYSIS e yJ07
/prep7 `um,S
ET,1,PLANE2 ^[tE^(|T
keyopt,1,3,2 pFd8p@m_2
Bvn3:+(47
*SET,R,0.7 "n!yK
*SET,H,10.0 YZBh}l6t
*SET,X1,-2*R d]l8ei@>h
*SET,Y1,-2*R kW g.-$pp
*SET,W1,4*R e{P v:jl
*SET,H1,4*R c0@8KW[,
-Ks>s
*SET,X2,-10.0 lS.Adl^k
*SET,Y2,H-20.0 w6%
Q"%rp
*SET,W2,20.0 aKbmj
*SET,H2,20.0 #dA$k+3
CYL4,0,0,0,45,R,405,0 6gg8h>b
BLC4,X1,Y1,W1,H1 }9'`3vsJ
BLC4,X2,Y2,W2,H2 $E\|\g
AOVL,1,2,3 :jLL IqhB
NUMCMP,ALL Z .6dL
NUMMRG,ALL,,,,LOW -1g:3'%
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LANG,11,8,90,, hi0HEm\
LANG,11,7,90,, 8-#%l~dr
LANG,10,7,90,, G21o@38e
LANG,10,6,90,, g\JJkXjD#
LANG, 9,6,90,, yp.K-
LANG, 9,5,90,, V0\[|E;F
LANG,12,5,90,, H$(bSw$
LANG,12,8,90,, Wp=3heCa6
L,1,7 &N|$G8\CY
L,2,8 ATNOb
L,3,5 Iry$z^
L,4,6 1PkCWRpR
NUMCMP,ALL R2~Tr$:
NUMMRG,ALL,,,,LOW 5yy:JTAH5
FLST,3,4,4,ORDE,2 iEr,ly
FITEM,3,29 `C+<!)2
FITEM,3,-32 []>'Dw_r
ASBL,2,P51X @!#e\tx
FLST,3,8,4,ORDE,8 FRBu8WW0L
FITEM,3,14 T
pkSY`T
FITEM,3,16 n{;j
FITEM,3,18 qos7u91z
FITEM,3,20 )u)=@@k21
FITEM,3,22 u*l|MIi6J
FITEM,3,24 &7aWVKon
FITEM,3,26 <$(B [T
FITEM,3,28 e`D}[G#
ASBL, 3,P51X ^/2I)y]W0
NUMCMP,ALL L[G O6l
NUMMRG,ALL,,,,LOW @p+;iS1}
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!初始参数 9oWU]A\k>
MP,EX,1,3.0E6 %iN>4;T8
MP,PRXY,1,0.33 !+T1kMP+l
MP,DENS,1,1900.0 &v{Ehkr*
TB,DP,1 |W">&Rb<t#
TBDATA,1,2.4E4,13.6,0 zH8E,)
@c3xUK
MP,EX,2,3.0E6 NI >%v
MP,PRXY,2,0.33 &_ekA44E
MP,DENS,2,1900.1 4>hHUz[_
TB,DP,2 QU|_
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TBDATA,1,2.4E4,13.6,0 iq(PC3e`V
a:h<M^n049
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!剖分单元 'pdTV:]zA
type,1 cj/`m$
MAT,1 XIHN6aQ{X
lsel,S,line,,1,8,1 I{`7 0
lsel,A,line,,15,27,4 _!\d?]Ya
Lesize,ALL,,,4,,,,,0 wHc
my
lsel,S,line,,29,32,1 Lx^ eaP5
Lesize,ALL,,,3,,,,,0 HGDrH
/U~|B.z@6
lsel,S,line,,9,13,2 l90mM'[
lsel,A,line,,18,20,2 \*xB<mq
lsel,A,line,,21 :]^e-p!z
lsel,A,line,,26,28,2 >Jz9wo`
Lesize,ALL,,,10,,,,,0 ~&?bU]F
lsel,S,line,,10 y>^^.
lsel,A,line,,22 &XP(D5lf`B
lsel,A,line,,24,25,1 IHl q27O
Lesize,ALL,,,20-H-2*R,,,,,0 Bh>L"'.2
lsel,S,line,,12,14,2 ^OR0Vp>L
lsel,A,line,,16,17,1 d8j1L/e
Lesize,ALL,,,H-2*R,,,,,0 N@q}eGe
asel,s,area,,2,13,1 P#,u9EIJ
amesh,all g`7XE
QHEtG2
type,1 "F<CGSo
MAT,2 kmI0V[Y
asel,s,area,,1
BX,)G HE
amesh,all >ZgzE
nummrg,all,,,,low Aw o)a8e
numcmp,all z$32rt8{`v
RK>Pe3<
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!计算初始应力场 k_al*iM>H
/solu K7+yU3
antype,static 1j<(?MT-
deltim,0.1,0.05,0.2 WSkGVQu
autots,on !使用自动时间步 z ^gJy,T
pred,on !打开时间步长预测器 6o3
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lnsrch,on !打开线性搜索 K}VCFV
nlgeom,on !打开大位移效果 mPV<a&U
nropt,full !设定牛顿-拉普森选项 O !L`0
=%c
cnvtol,f,,0.02,0 kSQ8kU_w+
Nsel,s,loc,x,-10 VM"cpC_8
Nsel,a,loc,x,10 Ccf/hA#mb
D,all,,,,,,UX,,,,, AZtS4]4G)
Nsel,s,loc,y,H-20 +eM${JyXH
D,all,,,,,,Uy,,,,, a|aVc'j
time,1 /0h
*(nL
acel,,10 rH+OXGoB
nsel,all <j'V}|3
esel,all 3FEJ
9ZyG
allsel,all
l] nt@0+
solve b'H'QY
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!开挖 _FLEz|%~
time,2 RpHlq
esel,s,type,,2 ^.SYAwL
ekill,all ;?-AFd\i
nsel,all RgE`H r
esel,all o`?rj!\
allsel,all "/#JC}]
solve woYD &Oml
fini tT$OnZu&
?9b9{c'an
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!地表沉降 &1xCPKIr
!/POST1 +]db-
!LCDEF,1,1,, xvr5$x|h
!LCDEF,2,2,, *2'8d8>R%]
!LCASE,2, %`vzQt`>
!LCOPER,SUB,1, ,2, K"}fD;3
!Nsel,s,loc,Y,H w2)Ro:G
!PLVECT,U, , , ,VECT,ELEM,ON,0 _]Hna <Ly
!PLNSOL, U,Y, 0,1.0 ou|emAV
BT$p~XB
DX>a0-Xj
n/H
OP
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