在做隧道ANSYS简单开挖模拟时,出现了一些问题,望各位前辈给多多指教! 'QV4=h`
gvU6p[ D
隧道洞泾假定为1.0m(实际上不可能这么小,仅仅是数值实验),隧洞轴线左右及下部各取10m为边界,施加法向约束。 V+Tj[:ok
LTY.i3
通过APDL命令,改变隧道的轴线埋深,采取全断面一次性开挖,整个荷载步分为两步:第一步计算初始应力场,第二步是杀死 d)G-K+&B
JV/,QWar
开挖体单元,计算开挖后引起的地表沉降(位移场,第二步减去第一步),计算结果发现: )T3wU~%
_N]yI0k(
隧道的轴线埋深越浅,计算得到的地表沉降越小,这与工程实际不符,请问原因何在? w}1)am&pD
m:41zoV
以下是我的计算命令流,希望得到高手的帮助啊! =0:hrg+Zgx
{'ZnxK'
;I7Z*'5!
Fini 7uDUZdJy
/clear /.?\P#9)
/title,TUNNEL ANALYSIS an7N<-?
/prep7 RTU:J67E
ET,1,PLANE2 zV&3l9?U
keyopt,1,3,2 67g/(4 &
fBF}-{VX(
*SET,R,0.7 k@Tt,.];
*SET,H,10.0 UB1/FM4~
*SET,X1,-2*R B 3h<K}
*SET,Y1,-2*R + mcN6/
*SET,W1,4*R UEe qk"t^
*SET,H1,4*R hB.dqv]^
s=nds"J
*SET,X2,-10.0 !^7:Rr_
*SET,Y2,H-20.0 Kq?7#,_
*SET,W2,20.0 'I P!)DS
*SET,H2,20.0 f65Sr"qB3
CYL4,0,0,0,45,R,405,0 y,x~S\>+
BLC4,X1,Y1,W1,H1 MQ+ek4
BLC4,X2,Y2,W2,H2 4mAtYm
AOVL,1,2,3 ` WB|h)Y
NUMCMP,ALL QXz!1o+"
NUMMRG,ALL,,,,LOW 4(&'V+o
LANG,11,8,90,, ~4^e a
LANG,11,7,90,, O92Y d$S
LANG,10,7,90,, !+6l.`2WI
LANG,10,6,90,, |l|]Tw
LANG, 9,6,90,, xpxm9ySwu
LANG, 9,5,90,, 4{?x(~
LANG,12,5,90,, Lv4=-mWv&0
LANG,12,8,90,, 'SieZIm)
L,1,7 OS
6 )`
L,2,8 QD<4(@c5|
L,3,5 ?*@h]4+k'
L,4,6 _e3'f:
NUMCMP,ALL ?MYD}`Cv
NUMMRG,ALL,,,,LOW EyeLC6u
FLST,3,4,4,ORDE,2 uM}O8N
FITEM,3,29 yU.0'r5uR
FITEM,3,-32 v(^rq
ASBL,2,P51X f+6l0@K2
FLST,3,8,4,ORDE,8 x\DkS,O
FITEM,3,14 Ae#6=]V+^
FITEM,3,16 NIfc/%
FITEM,3,18 54{"ni2a
FITEM,3,20 $T4PC5.
FITEM,3,22 $ZU(bEUOG
FITEM,3,24 J]0#M:w&
FITEM,3,26 hvyN8We
FITEM,3,28 k +Oq$Pi
ASBL, 3,P51X {dwV-qz
NUMCMP,ALL !D3}5A1,
NUMMRG,ALL,,,,LOW D'h2 DP!
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!初始参数 3$8}%?i
MP,EX,1,3.0E6 +7^Ul6BB#K
MP,PRXY,1,0.33 07|NPS
MP,DENS,1,1900.0 4.'EEuRw\}
TB,DP,1 o^?{j*)g
TBDATA,1,2.4E4,13.6,0 zEW:Xe)
;$QJnQ"R
MP,EX,2,3.0E6 m}9V@@
MP,PRXY,2,0.33 }'W^Ki$
MP,DENS,2,1900.1 aK{\8L3]
TB,DP,2 >{S $0D
TBDATA,1,2.4E4,13.6,0 yLx.*I^6
FQFENq''B
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!剖分单元 pqSE|3*l
type,1 $D5U#
MAT,1 I[UA' ~f
lsel,S,line,,1,8,1 X$9QW3.M
lsel,A,line,,15,27,4 cPcV[6)5K9
Lesize,ALL,,,4,,,,,0 ?/(K7>`
lsel,S,line,,29,32,1 Xoy 1Gi?
Lesize,ALL,,,3,,,,,0 F4x7;?W{*
6iG<"{/U5
lsel,S,line,,9,13,2 lt4jnV2"a
lsel,A,line,,18,20,2 ,[\(U!Z7:%
lsel,A,line,,21 0UJ`<Bfd
lsel,A,line,,26,28,2 @<G/H|f
Lesize,ALL,,,10,,,,,0 hD1AK+y
lsel,S,line,,10 _6!/}Fm
lsel,A,line,,22 -y?Z}5-rs
lsel,A,line,,24,25,1 `tG_O
Lesize,ALL,,,20-H-2*R,,,,,0 >!1 f`
lsel,S,line,,12,14,2 SN(=e#ljE
lsel,A,line,,16,17,1 p2vBj. *J
Lesize,ALL,,,H-2*R,,,,,0 a*j <TR
asel,s,area,,2,13,1 +{%(_<
amesh,all u;Eu<jU1
x\.i`ukx
type,1 C|\^uR0
MAT,2 &8_;:
asel,s,area,,1 +^?-}v
amesh,all 7omGg~!k(
nummrg,all,,,,low =h::VB}Lv
numcmp,all &ZN'Ey?
J&:W4\ m
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!计算初始应力场 *\KMkx
/solu GB?#1|,
antype,static @$d\5Q(G
deltim,0.1,0.05,0.2 t`T\d\
autots,on !使用自动时间步 i*R:WTw#
pred,on !打开时间步长预测器 4~A#^5J
lnsrch,on !打开线性搜索 -]\E}Ti
nlgeom,on !打开大位移效果 S7ehk*`
nropt,full !设定牛顿-拉普森选项 )8 :RiG2B
cnvtol,f,,0.02,0 C;q}3c*L
Nsel,s,loc,x,-10 W 8$=a
Nsel,a,loc,x,10 P0 ltN
D,all,,,,,,UX,,,,, )O@^H
Nsel,s,loc,y,H-20 ~f10ZB_k>'
D,all,,,,,,Uy,,,,, BhW]Oq&
time,1 gAA
%x7
acel,,10 V`,[=u?c
nsel,all xdfvme[
esel,all -`dxx)x
allsel,all v*~%x
solve J(0 =~Z[
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!开挖 {]\uR-a(o
time,2 rtL9cw5
esel,s,type,,2 ./nYXREO|
ekill,all on;sq8;
nsel,all *{dD'9Bg
esel,all ZqbM%(=z(`
allsel,all 1mn$Rh&dO
solve xrVZxK:!
fini n5k^v$'
s$>m0^
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!地表沉降 1gShV ]2
!/POST1 i %hn
!LCDEF,1,1,, B:- KZuO
!LCDEF,2,2,, /-{O\7-D
!LCASE,2, wGzXp5
dl
!LCOPER,SUB,1, ,2, ONN{4&7@<
!Nsel,s,loc,Y,H ,rFLpQl
!PLVECT,U, , , ,VECT,ELEM,ON,0 |<3Q+EB^
!PLNSOL, U,Y, 0,1.0 O&gwr
"UoCT7X
*K jVPs
]u4>;sa
udEb/7ZL