在做隧道ANSYS简单开挖模拟时,出现了一些问题,望各位前辈给多多指教! :==UDVP
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隧道洞泾假定为1.0m(实际上不可能这么小,仅仅是数值实验),隧洞轴线左右及下部各取10m为边界,施加法向约束。 &Z#Vw.7U
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通过APDL命令,改变隧道的轴线埋深,采取全断面一次性开挖,整个荷载步分为两步:第一步计算初始应力场,第二步是杀死 r>n8`W
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开挖体单元,计算开挖后引起的地表沉降(位移场,第二步减去第一步),计算结果发现: `K1PGibV
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隧道的轴线埋深越浅,计算得到的地表沉降越小,这与工程实际不符,请问原因何在? e!O &~#'h}
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以下是我的计算命令流,希望得到高手的帮助啊! O:5ldI
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Fini oZ|{J
/clear &q kl*#]
/title,TUNNEL ANALYSIS dA3`b*nC
/prep7
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keyopt,1,3,2 ZVCv(J
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*SET,R,0.7 *GY,h$Ul
*SET,H,10.0 y"{UNM|R
*SET,X1,-2*R dW] Ej"W
*SET,Y1,-2*R 9
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*SET,W1,4*R C 6:p Y-
*SET,H1,4*R ^+YGSg7
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*SET,X2,-10.0 `qQQQ.K7)z
*SET,Y2,H-20.0 2g`uC}
*SET,W2,20.0 Fp* &os
*SET,H2,20.0 l a6e`
CYL4,0,0,0,45,R,405,0 aG8;,H=%,
BLC4,X1,Y1,W1,H1 2n\i0?RD
BLC4,X2,Y2,W2,H2 O>{t}6o
AOVL,1,2,3 D0"yZp}
NUMCMP,ALL JN9H T0
NUMMRG,ALL,,,,LOW B@:XC&R^
LANG,11,8,90,, wZ#~+ }T
LANG,11,7,90,, `^@g2c+d
LANG,10,7,90,, QyBK*uNdV
LANG,10,6,90,, $(!D/bvJ
LANG, 9,6,90,, pNk,jeo
LANG, 9,5,90,, _16&K}<
LANG,12,5,90,, 9fk\Ay1P
LANG,12,8,90,, .,(uoK{
L,1,7 kgib$t_7
L,2,8 `XRb:d^
L,3,5 7cQHRM+1
L,4,6 _a:!U^4
NUMCMP,ALL :D)&>{?
NUMMRG,ALL,,,,LOW ocuNrkZ
FLST,3,4,4,ORDE,2 >H]|A<9u(
FITEM,3,29 gEe W1:AB
FITEM,3,-32 X_Of k
ASBL,2,P51X {e!uvz,e
FLST,3,8,4,ORDE,8 D=Yag!1
FITEM,3,14 ~N+/ZVo&y
FITEM,3,16 2&G1Q'!
FITEM,3,18 uR[PKLh
FITEM,3,20 #h|,GvmF<b
FITEM,3,22 71,0v`Z<
FITEM,3,24 mU0r"\**c3
FITEM,3,26 `
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FITEM,3,28 kkuQ"^<J
ASBL, 3,P51X &B>uPZ]
NUMCMP,ALL [n@!=T
NUMMRG,ALL,,,,LOW =Z$=-\<x0.
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!初始参数 Eo3Aak o
MP,EX,1,3.0E6 wh[:wE]eX
MP,PRXY,1,0.33 F<'l'AsC-
MP,DENS,1,1900.0 HZ`G)1&)
TB,DP,1 @R Yb-d
TBDATA,1,2.4E4,13.6,0 cbHn\m)J,
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MP,EX,2,3.0E6 0jx~_zq-j
MP,PRXY,2,0.33 OrqJo!FEg{
MP,DENS,2,1900.1 8f`b=r(a>
TB,DP,2 %l$&_xV-
TBDATA,1,2.4E4,13.6,0 , $F0D
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!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!剖分单元 ff+9(P>*
type,1 R S_lQ{'
MAT,1 $5p'+bE
lsel,S,line,,1,8,1 u:>3j,Cs
lsel,A,line,,15,27,4 Ydd>A\v\;
Lesize,ALL,,,4,,,,,0 -W"0,.Dvg
lsel,S,line,,29,32,1 V<R+A* gY:
Lesize,ALL,,,3,,,,,0 X QoT},C
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lsel,S,line,,9,13,2 d+| !6
lsel,A,line,,18,20,2 f0`rJ?us
lsel,A,line,,21 }(7QJk5 j
lsel,A,line,,26,28,2 R~?; KJ
Lesize,ALL,,,10,,,,,0 o_^d>Klb8
lsel,S,line,,10 'f<_SKd
lsel,A,line,,22 k=/|?%
lsel,A,line,,24,25,1 %' g-%2C?
Lesize,ALL,,,20-H-2*R,,,,,0 wjGjVTtHs
lsel,S,line,,12,14,2 <$Kv^Y *
lsel,A,line,,16,17,1 h[)aRo
Lesize,ALL,,,H-2*R,,,,,0 &!EYT0=>p
asel,s,area,,2,13,1 Nk~dfY<s
amesh,all K@u."eaD
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type,1 QZq9$;>dW
MAT,2 v\tbf
asel,s,area,,1 uNGxz*e
amesh,all WHk/mAI-s
nummrg,all,,,,low ^%/5-0?xE
numcmp,all FwzA_
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!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!计算初始应力场 ?cxK~Y\
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antype,static l,2z5p
deltim,0.1,0.05,0.2 L/+J|_J)
autots,on !使用自动时间步 g#2X'%&+
pred,on !打开时间步长预测器 4E(5Ccb
lnsrch,on !打开线性搜索 -"tgEC\tD
nlgeom,on !打开大位移效果 NB#*`|qt
nropt,full !设定牛顿-拉普森选项 hd
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cnvtol,f,,0.02,0 aw~EK0yU
Nsel,s,loc,x,-10 ~F6gF7]z
Nsel,a,loc,x,10 ?B!ZqJ#
D,all,,,,,,UX,,,,, ^W05Z!}
Nsel,s,loc,y,H-20 UN 4)>\Y
D,all,,,,,,Uy,,,,, `*!>79_2C
time,1 YGmdiY:;1
acel,,10 qiryC7.E
nsel,all |6Z MxY
esel,all w1G.^
allsel,all YfU#kvE'
solve ?YykCJJ ~@
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!开挖 0qUap*fvC
time,2 ABDUp:
esel,s,type,,2 6EWB3.x19
ekill,all A>2p/iMc
nsel,all OYy !4Fp
esel,all Czxrn2p/
allsel,all JB_`lefW,'
solve E\N=p&g$
fini EZfa0jJD
4^^rOi0
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!地表沉降 [LDzR7vnf
!/POST1 lM%fgyX
!LCDEF,1,1,, 291|KG
!LCDEF,2,2,, v('d H"Y
!LCASE,2, Y/(-mcR
!LCOPER,SUB,1, ,2, :vT%5CQ
!Nsel,s,loc,Y,H qE:DJy<
!PLVECT,U, , , ,VECT,ELEM,ON,0 V gk,+l!4
!PLNSOL, U,Y, 0,1.0 I,3!uogn
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