地基处理技术规范规定相当明确, _-BP?'lN
一例子: D\M"bf>q1
5Pf=Uj6D
CFG桩复合地基沉降量验算: \^6 [^\@[
基础宽度(m)b= 1.2 附加压力(Kpa)P0= 260 "BsK'yo.
Zi Zi/b αi Zi*αi ΔZi*αi Esi P0/Esi ΔSi ΣΔSi ΔSi/ΣΔSi nA0%M1a
0.30 0.250 0.9800 0.294 0.294 50.0 5.200 1.529 1.529 1.000 N!ihj:,
0.80 0.667 0.8528 0.682 0.388 30.0 8.667 3.365 4.894 0.688 z&QfZs
2.00 1.667 0.6720 1.344 0.662 13.9 18.739 12.401 17.294 0.717 xc*a(v0
3.70 3.083 0.6064 2.244 0.900 112.0 2.321 2.089 19.383 0.108 aX1b(h2
4.80 4.000 0.5240 2.515 0.272 22.5 11.556 3.138 22.520 0.139 ?j8!3NCl}
7.40 6.167 0.4772 3.531 1.016 30.0 8.667 8.806 31.326 0.281 %}(`?
11.80 9.833 0.3600 4.248 0.717 40.0 6.500 4.659 35.985 0.129 M(L6PyEa!Y
12.10 10.083 0.3520 4.259 0.011 40.0 6.500 0.073 36.058 0.002 U;/2\Ii
压缩模量当量值 =30.7,则 =0.20, L ~'98C
则地基最终沉降量36.10×0.20=7.3MM。压缩层下限按变形比控制在0.025限比以内。