命令流解析 [复制链接]

请回复也是一种美德，我也不容易，呵呵  xiQc\k$  
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FLAC3D3.0在某隧道工程开挖支护中的应用 ;9fW
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隧道建模命令流入下： '4
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set log on _Gb7n5p  
set logfile yang.log W>?aZv  
gen zon radcyl p0 0 0 0 p1 9.0 0 0 p2 0 50 0 p3 0 0 8 & ,1!Y!,xy  
size 4 20 6 4 dim 6 5 6 5 rat 1 1 1 1 group 围岩 g2}aEfp!H  
gen zon cshell p0 0 0 0 p1 6.0 0 0 p2 0 50 0 p3 0 0 5.0 & UUtSme  
size 4 20 6 4 dim 5.6 4.6 5.6 4.6 rat 1 1 1 1 group 初期支护 F.(e}EMyNh  
gen zon cshell p0 0 0 0 p1 5.6 0 0 p2 0 50 0 p3 0 0 4.6 & .wWf#bB  
size 4 20 6 4 dim 5.0 4.0 5.0 4.0 rat 1 1 1 1 group 二次衬砌 fill group 原岩 n!~QC  
gen zon radcyl p0 0 0 0 p1 0 0 -8.0 p2 0 50 0 p3 9.0 0 0 & e.(d?/!F_  
size 4 20 6 4 dim 3 6 3 6 rat 1 1 1 1 group 围岩2 0R+p\Nc&1  
gen zon cshell p0 0 0 0 p1 0 0 -3.0 p2 0 50 0 p3 6.0 0 0 & ygm6(+  
size 4 20 6 4 dim 2.6 5.6 2.6 5.6 rat 1 1 1 1 group 仰拱初期支护 KyDd( 'i  
gen zon cshell p0 0 0 0 p1 0 0 -2.6 p2 0 50 0 p3 5.6 0 0 & S
x Bo%  
size 4 20 6 4 dim 2 5 2 5 rat 1 1 1 1 group 仰拱二次衬砌 fill group 仰拱原岩 q3-cWfU  
gen zone reflect normal -1 0 0  ;0$qT$,  
gen zone radtun p0 0 0 0 p1 45 0 0 p2 0 50 0 p3 0 0 20 & y,KZp2 j  
size 3 20 3 12 dim 9 8 9 8 rat 1 1 1 1.1 group 围岩3 )' ,dP)b  
gen zon reflect dip 0 ori 0 0 0 range x 0 9 y 0 50 z 8 20 n>:e8KVM;  
gen zon reflect dip 0 ori 0 0 0 range x 9 45 y 0 50 z 0 20 SX =^C  
gen zon reflect dip 90 dd 270 ori 0 0 0 range x 0 9 y 0 50 z 8 20 qPUACuF'  
gen zon reflect dip 90 dd 270 ori 0 0 0 range x 0 9 y 0 50 z -8 -20 #Q_<eo%lI*  
gen zon reflect dip 90 dd 270 ori 0 0 0 range x 9 45 y 0 50 z -20 20 P@n rcgM.  
gen zon brick p0 -45 0 -20 p1 -45 0 -40 p2 -45 50 -20 p3 45 0 -20 & H15!QxD#  
size 5 20 6 rat 1.1 1 1 group 围岩4 \k6OP  
save tun_model.sav &`>dY /Y  
假设围岩岩体符合mohr-coulomb本构模型，给围岩赋参数命令流如下， 4\ )WMP  
; mohr-coulomb model p<Tg}fg  
model mohr MIZ!+[At  
def derive $:-C9N29  
s_mod1=E_mod1/(2.0*(1.0+p_ratio1)) [xGL0Z%)t  
b_mod1=E_mod1/(3.0*(1.0-2.0*p_ratio1)) ,,IK}  
s_mod2=E_mod2/(2.0*(1.0+p_ratio2)) .{bT9S
c5  
b_mod2=E_mod2/(3.0*(1.0-2.0*p_ratio2)) "]'W^Fg  
end ?vF8 y;Jh  
set E_mod1=0.6e9 p_ratio1=0.27 E_mod2=0.8e9 p_ratio2=0.26 dvY3=~'  
derive (r'NB  
prop bulk b_mod1 shear s_mod1 cohe 1.8e6 tens 0.8e6 fric 30 range z 4.5 20 sT<h+[2d  
prop bulk b_mod2 shear s_mod2 cohe 2.8e6 tens 1.0e6 fric 35 range z -40 4.5 kDE:KV<"c  
ini dens=2300 wa&:86~l?  
set grav 0 0 -10 ,m7Z w_.  
; boundary and initial conditions -cZuP7oA  
apply szz -1.4e6 range z 19.9 20.1 EL2z&  
fix z range z -40.1 -39.1 z5<&}Vh;P  
fix x range x -45.1 -44.9 2JeEmG9  
fix x range x 44.9 45.1 (5y*Btd=  
fix y range y 49.9 50.1 [!} uj`e  
hist unbal A]o3MoSt  
hist gp xdis 6.0,0,0 @^-f+o  
hist gp zdis 0,0,5 8F)9.s,*  
hist gp xdis 6.0,50,0 }095U(@  
hist gp zdis 0,50,5 &?y|Pn  
plot hist 3 ov\%*z2=  
solve |\"%Dy[m  
save tun_nature.sav Q'ib7R;V,  
对后面计算而言，模型建立时岩体在开挖前认为位移已经终了，因此需要对位移进行“清零”，而应力可以保留。假设隧道先开挖上断面，中间不设支护，直到进尺50m，那么此时位移和应力的分布情况可用如下命令流 ww%4MHPp8  
ini xdis=0 ydis=0 zdis=0 Zw/??Tq b  
plot re QZO<'q`L  
model null range group 原岩 4 BNbS|?vV  
model null range group 二次衬砌 +:
c}LCI9<  
model null range group 初期支护 &#~U1: 0  
set large ,g|ht%"  
hist unbal K&=6DvfR  
plot hist 3 :,/ \E  
solve ]^a{?2ei  
save tun_ext1.sav XC390t  
如果在开挖后适时对隧道进行锚喷混凝土初期支护，该命令流如下： |qf9-36  
restore tun_nature.sav y|9 LtQ  
ini xdis=0 ydis=0 zdis=0 *l0i}"T^_  
plot re @}
+B%R  
model null range group 初期支护 GIR12%-EO  
model null range group 二次衬砌 -wNhbV2  
model null range group 原岩 ^;\6ju2  
step 100 o@} qPvt0  
hist unbal Kl(u~/=6  
plot hist 3 ;t@^Z_z,CR  
mo el range group 初期支护 ~aL?{kb+  
prop bulk 1.33e9 shear 0.8e9 cohe 2.2e6 tens 1.2e6 fric 32 range z 4.5 7.0 x -7.0 7.0 d)$seZB  
prop bulk 10.9e9 shear 8.9e9 dens 2500 range group 初期支护 bOV]!)o  
set large t)(>E'X x  
solve Nii5},  
save tun_ext2.sav

虽然我不懂 不过你不错！回复下   

好好看看，谢谢那些黑夜里为大家带来光明的同志们！谢谢你们的好资料！

FLAC3D3.0在某隧道工程开挖支护中的应用 U7g,@/Qx   gkx<<)y l  
隧道建模命令流入下： ieWXr4@:   /"1[qT\F  
set log on (|<+yQ,@>   5*$z4O:Aa  
set logfile yang.log +eKLwM   `M_w^&6+n  
gen zon radcyl p0 0 0 0 p1 9.0 0 0 p2 0 50 0 p3 0 0 8 & /F|VYl^_   [{+ZQd  
size 4 20 6 4 dim 6 5 6 5 rat 1 1 1 1 group 围岩 L\bc R   %9t=Iu*  
gen zon cshell p0 0 0 0 p1 6.0 0 0 p2 0 50 0 p3 0 0 5.0 & 3KkJQ5a   &v+Hl^  
size 4 20 6 4 dim 5.6 4.6 5.6 4.6 rat 1 1 1 1 group 初期支护 =1)9>=}   cW^u4%f't'  
gen zon cshell p0 0 0 0 p1 5.6 0 0 p2 0 50 0 p3 0 0 4.6 & <1x u&Z7   E `%*lGu_  
size 4 20 6 4 dim 5.0 4.0 5.0 4.0 rat 1 1 1 1 group 二次衬砌 fill group 原岩 vJ 28A   jSvo-  
gen zon radcyl p0 0 0 0 p1 0 0 -8.0 p2 0 50 0 p3 9.0 0 0 & **1=|aa:   g8Zf("  
size 4 20 6 4 dim 3 6 3 6 rat 1 1 1 1 group 围岩2 Y(T$k9%}+  
"fd'~e$S#  
gen zon cshell p0 0 0 0 p1 0 0 -3.0 p2 0 50 0 p3 6.0 0 0 & M A%g-}   %-NG eN8  
size 4 20 6 4 dim 2.6 5.6 2.6 5.6 rat 1 1 1 1 group 仰拱初期支护 !g|[A7<|   7{=+Va5  
gen zon cshell p0 0 0 0 p1 0 0 -2.6 p2 0 50 0 p3 5.6 0 0 & |GPY bxzc   <bBgevL+_K  
size 4 20 6 4 dim 2 5 2 5 rat 1 1 1 1 group 仰拱二次衬砌 fill group 仰拱原岩 ,#0#1k<Dm   (*!4O>]  
gen zone reflect normal -1 0 0 FS!vnl8`   GIUyW  
gen zone radtun p0 0 0 0 p1 45 0 0 p2 0 50 0 p3 0 0 20 & N>sH T =_   qKuHd~M{ 1  
size 3 20 3 12 dim 9 8 9 8 rat 1 1 1 1.1 group 围岩3 D&],.N   :Ui'x8yt  
gen zon reflect dip 0 ori 0 0 0 range x 0 9 y 0 50 z 8 20 3YUF\L]yyw   }iB>3|\  
gen zon reflect dip 0 ori 0 0 0 range x 9 45 y 0 50 z 0 20 _tQM<~Y]u\   H<`7){iG  
gen zon reflect dip 90 dd 270 ori 0 0 0 range x 0 9 y 0 50 z 8 20 aHitPPlq   Z2k5qs7g  
gen zon reflect dip 90 dd 270 ori 0 0 0 range x 0 9 y 0 50 z -8 -20 .i#'IS0c   L i`OaP$  
gen zon reflect dip 90 dd 270 ori 0 0 0 range x 9 45 y 0 50 z -20 20 <Y;w I#C   ` B+Pl6l)F  
gen zon brick p0 -45 0 -20 p1 -45 0 -40 p2 -45 50 -20 p3 45 0 -20 & WK{F   F;Ubdxwwl  
size 5 20 6 rat 1.1 1 1 group 围岩4 f&Juq8s_0   P?iQ{x}w~  
save tun_model.sav PT4iy<   |c,'0V,"cH  
假设围岩岩体符合mohr-coulomb本构模型，给围岩赋参数命令流如下， lpbcpB   93Qx+oK]  
; mohr-coulomb model sv6 m)pwh   E0Kt4%b  
model mohr @)ls+}=Y   ob(~4H-
 
def derive @qB>qD~WsD   _eaK:EW  
s_mod1=E_mod1/(2.0*(1.0+p_ratio1))  I*n]8c   k@2@%02o9C  
b_mod1=E_mod1/(3.0*(1.0-2.0*p_ratio1)) tY#Zl 54~{   3HX-lg`0  
s_mod2=E_mod2/(2.0*(1.0+p_ratio2)) E,Xl8rC   ]5eZLXM  
b_mod2=E_mod2/(3.0*(1.0-2.0*p_ratio2)) XQ8q)B=   hXn@vK6  
end 3jHE,5m   yfe4}0}  
set E_mod1=0.6e9 p_ratio1=0.27 E_mod2=0.8e9 p_ratio2=0.26 qI<c47d;q   T@N)BfkB  
derive #8y"1I=i&   2|8$@*-\  
prop bulk b_mod1 shear s_mod1 cohe 1.8e6 tens 0.8e6 fric 30 range z 4.5 20 tqjjn5!   6uWPIM;  
prop bulk b_mod2 shear s_mod2 cohe 2.8e6 tens 1.0e6 fric 35 range z -40 4.5 e7plL^^`   YzAGhAyw  
ini dens=2300 D$E#:[   #j"N5e}U  
set grav 0 0 -10 ]@}o"Td   };8PPR)\y  
; boundary and initial conditions _nSEp >]L   ~T'$gl  
apply szz -1.4e6 range z 19.9 20.1 ubc k{\.   L0xh?B  
fix z range z -40.1 -39.1 ?yu@eo   ')E4N+h/  
fix x range x -45.1 -44.9 b`f6(6   -$y/*'  
fix x range x 44.9 45.1 :z6?   88atj+N]  
fix y range y 49.9 50.1 (!Xb8rV0_   xEe3,tb'e  
hist unbal r$Ik* R   LO,k'gg<  
hist gp xdis 6.0,0,0 5r d t   3:!5 ]  
hist gp zdis 0,0,5 muKu@nshL   >vQKCc|93  
hist gp xdis 6.0,50,0 2 #cw_Ua   BOW`{=  
hist gp zdis 0,50,5 K1- RJj\L   lMXLd91  
plot hist 3 ZVit] 3hd   Xm.["&  
solve ?9?o8!   QPsvc6ds  
save tun_nature.sav X7gB.=\X   I;?np  
对后面计算而言，模型建立时岩体在开挖前认为位移已经终了，因此需要对位移进行“清零”，而应力可以保留。假设隧道先开挖上断面，中间不设支护，直到进尺50m，那么此时位移和应力的分布情况可用如下命令流 $"#M:V @   <d3N2  
ini xdis=0 ydis=0 zdis=0 !~ j9Oc^   mC`U"
rlK~  
plot re y{XNB}E   (_~Dyvo  
model null range group 原岩 M3dUGM   y@]:7  
model null range group 二次衬砌 5r;)P po   "eKM<S  
model null range group 初期支护 =w:H9uj6F   'jU;.vZex  
set large ZY;g)`E1   BH?fFe&J:`  
hist unbal h,]lN'JG{   v;R+{K87  
plot hist 3 R80|q#h,]   \YF'qWB  
solve ~u?rjkSFoh   IeE6?!,)  
save tun_ext1.sav 472 'P   fu`|@
S  
如果在开挖后适时对隧道进行锚喷混凝土初期支护，该命令流如下： 37V$Qb_   5'3H$%dC  
restore tun_nature.sav Exat_ L'?   DGx<Nys@B  
ini xdis=0 ydis=0 zdis=0 g](&H$g   T4"*w  
plot re U/7jK40   "& q])3h=  
model null range group 初期支护 >PGsY[N   x*F_XE1#M  
model null range group 二次衬砌 V0gu0+u~R   3#c0p790  
model null range group 原岩 / ]nrxT   LGC3"z\=  
step 100 (k%r_O 6   to'O;f">n  
hist unbal 4&~*;an7   AjO|@6  
plot hist 3 rE\&FVx   D?? \H\  
mo el range group 初期支护 `oE.$~'   jR,3-JQ  
prop bulk 1.33e9 shear 0.8e9 cohe 2.2e6 tens 1.2e6 fric 32 range z 4.5 7.0 x -7.0 7.0 Ge76/T%{Q   CK} _xq2b  
prop bulk 10.9e9 shear 8.9e9 dens 2500 range group 初期支护 M/}i7oS]   dv\aP  
set large QX9['B<   aw'o=/a8  
solve _%aT3C}k   'ewVn1ME[  
save tun_ext2.sav

谢谢谢谢！！！！！

看得出楼主是为高手！！

相当不错，得好好学习一下

很不错 ,[ M^rv  
值得学习 q#1CmKt4R  

学习 学习

模拟下试试

不错啊，学习

无论如何，表示感谢，不能只偷看不感谢！